The third zero is -b/a

=>Two zeroes [ p, q ] = 0, 0

=>Sum of roots = -b/a

Therefore,

=>p + q + r = -b / a

=>0 + 0 + r = -b / a

=> r = -b/a

=>Third zero = r = -b/a

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## Answers & Comments

Answer:The third zero is -b/a

## Step-by-step explanation:

## Given:

## Two of the zeroes of the cubic polynomial ax³ + bx² + cx + d are 0

## Let zeroes of the equation be p, q, r

## According to question,

=>Two zeroes [ p, q ] = 0, 0

## We know,

=>Sum of roots = -b/a

Therefore,

## By using relation between zeroes and coefficient of polynomial, we have:

=>p + q + r = -b / a

## Substituting the values of p and q,

=>0 + 0 + r = -b / a

=> r = -b/a

=>Third zero = r = -b/a

## Hence,

## The third zero is -b/a

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